101934: [AtCoder]ABC193 E - Oversleeping
Description
Score : $500$ points
Problem Statement
A train goes back and forth between Town $A$ and Town $B$. It departs Town $A$ at time $0$ and then repeats the following:
- goes to Town $B$, taking $X$ seconds;
- stops at Town $B$ for $Y$ seconds;
- goes to Town $A$, taking $X$ seconds;
- stops at Town $A$ for $Y$ seconds.
More formally, these intervals of time are half-open, that is, for each $n = 0, 1, 2, \dots$:
- at time $t$ such that $(2X + 2Y)n ≤ t < (2X + 2Y)n + X$, the train is going to Town $B$;
- at time $t$ such that $(2X + 2Y)n + X ≤ t < (2X + 2Y)n + X + Y$, the train is stopping at Town $B$;
- at time $t$ such that $(2X + 2Y)n + X + Y ≤ t < (2X + 2Y)n + 2X + Y$, the train is going to Town $A$;
- at time $t$ such that $(2X + 2Y)n + 2X + Y ≤ t < (2X + 2Y)(n + 1)$, the train is stopping at Town $A$.
Takahashi is thinking of taking this train to depart Town $A$ at time $0$ and getting off at Town $B$. After the departure, he will repeat the following:
- be asleep for $P$ seconds;
- be awake for $Q$ seconds.
Again, these intervals of time are half-open, that is, for each $n = 0, 1, 2, \dots$:
- at time $t$ such that $(P + Q)n ≤ t < (P + Q)n + P$, Takahashi is asleep;
- at time $t$ such that $(P + Q)n + P ≤ t < (P + Q)(n + 1)$, Takahashi is awake.
He can get off the train at Town $B$ if it is stopping at Town $B$ and he is awake.
Determine whether he can get off at Town $B$. If he can, find the earliest possible time to do so.
Under the constraints of this problem, it can be proved that the earliest time is an integer.
You are given $T$ cases. Solve each of them.
Constraints
- All values in input are integers.
- $1 ≤ T ≤ 10$
- $1 ≤ X ≤ 10^9$
- $1 ≤ Y ≤ 500$
- $1 ≤ P ≤ 10^9$
- $1 ≤ Q ≤ 500$
Input
Input is given from Standard Input in the following format:
$T$ $\rm case_1$ $\rm case_2$ $\hspace{9pt}\vdots$ $\rm case_T$
Each case is in the following format:
$X$ $Y$ $P$ $Q$
Output
Print $T$ lines.
The $i$-th line should contain the answer to $\rm case_i$.
If there exists a time such that Takahashi can get off the train at Town $B$, the line should contain the earliest such time; otherwise, the line should contain infinity
.
Sample Input 1
3 5 2 7 6 1 1 3 1 999999999 1 1000000000 1
Sample Output 1
20 infinity 1000000000999999999
Let $[a, b)$ denote the interval $a ≤ t < b$.
In the first case, the train stops at Town $B$ during $[5, 7), [19, 21), [33, 35), \dots$, and Takahashi is awake during $[7, 13), [20, 26), [33, 39), \dots$, so he can get off at time $20$ at the earliest.