103710: [Atcoder]ABC371 A - Jiro

Problem Statement

There are three brothers named A, B, and C. The age relationships among them are given by three characters $S_{\mathrm{AB}}, S_{\mathrm{AC}}, S_{\mathrm{BC}}$, which mean the following:

• If $S_{\mathrm{AB}}$ is <, then $A$ is younger than $B$; if it is >, then $A$ is older than $B$.
• If $S_{\mathrm{AC}}$ is <, then $A$ is younger than $C$; if it is >, then $A$ is older than $C$.
• If $S_{\mathrm{BC}}$ is <, then $B$ is younger than $C$; if it is >, then $B$ is older than $C$.

Who is the middle brother, that is, the second oldest among the three?

Constraints

• Each of $S_{\mathrm{AB}}, S_{\mathrm{AC}}, S_{\mathrm{BC}}$ is < or >.
• The input contains no contradictions; that is, there always exists an age relationship that satisfies all given inequalities.

Input

The input is given from Standard Input in the following format:

$S_{\mathrm{AB}}$ $S_{\mathrm{AC}}$ $S_{\mathrm{BC}}$

Output

Print the name of the middle brother, that is, the second oldest among the three.

Sample Input 1

< < <

Sample Output 1

B

Since $A$ is younger than $B$, and $B$ is younger than $C$, we can determine that $C$ is the oldest, $B$ is the middle, and $A$ is the youngest. Hence, the answer is B.

Sample Input 2

< < >

Sample Output 2

C

问题陈述

有三个兄弟，分别叫A、B和C。他们之间的年龄关系由三个字符$S_{\mathrm{AB}}$、$S_{\mathrm{AC}}$、$S_{\mathrm{BC}}$给出，这意味着以下内容：

• 如果$S_{\mathrm{AB}}$是<，那么$A$比$B$年轻；如果是>，那么$A$比$B$年长。
• 如果$S_{\mathrm{AC}}$是<，那么$A$比$C$年轻；如果是>，那么$A$比$C$年长。
• 如果$S_{\mathrm{BC}}$是<，那么$B$比$C$年轻；如果是>，那么$B$比$C$年长。

谁是中间的兄弟，也就是说，三个人中第二大的那个是谁？

约束条件

• $S_{\mathrm{AB}}$、$S_{\mathrm{AC}}$、$S_{\mathrm{BC}}$每个都是<或>。
• 输入不包含矛盾；也就是说，总是存在一个年龄关系能满足所有给定的不等式。

输入

输入从标准输入以下格式给出：

$S_{\mathrm{AB}}$ $S_{\mathrm{AC}}$ $S_{\mathrm{BC}}$

输出

打印中间兄弟的名字，即三个人中第二大的那个。

示例输入1

< < <

示例输出1

B

因为$A$比$B$年轻，$B$比$C$年轻，我们可以确定$C$是最年长的，$B$是中间的，$A$是最年轻的。因此，答案是B。

示例输入2

< < >

示例输出2

C