Two Bases

题意翻译

给你一个 $n$ 进制 $a$ 位整数 $x$ 和一个 $m$ 进制 $b$ 位整数 $y$， 比较 $x$ 与 $y$ 的大小。 输入： 第一行分别为 $a$ 和 $n$； 第二行 $a$ 个数分别为 $x$ 从高到低每一位上的数的十进制形式； 第三行分别为 $b$ 和 $m$；第四行的 $b$ 个数分别为 $x$ 从高到低每一位上的数的十进制形式。 输出： 若 $x>y,$ 输出 `>`； 若 $x<y,$ 输出 `<`； 若 $x=y,$ 输出 `=`。

题目描述

After seeing the "ALL YOUR BASE ARE BELONG TO US" meme for the first time, numbers $ X $ and $ Y $ realised that they have different bases, which complicated their relations. You're given a number $ X $ represented in base $ b_{x} $ and a number $ Y $ represented in base $ b_{y} $ . Compare those two numbers.

输入输出格式

输入格式

The first line of the input contains two space-separated integers $ n $ and $ b_{x} $ ( $ 1<=n<=10 $ , $ 2<=b_{x}<=40 $ ), where $ n $ is the number of digits in the $ b_{x} $ -based representation of $ X $ . The second line contains $ n $ space-separated integers $ x_{1},x_{2},...,x_{n} $ ( $ 0<=x_{i}&lt;b_{x} $ ) — the digits of $ X $ . They are given in the order from the most significant digit to the least significant one. The following two lines describe $ Y $ in the same way: the third line contains two space-separated integers $ m $ and $ b_{y} $ ( $ 1<=m<=10 $ , $ 2<=b_{y}<=40 $ , $ b_{x}≠b_{y} $ ), where $ m $ is the number of digits in the $ b_{y} $ -based representation of $ Y $ , and the fourth line contains $ m $ space-separated integers $ y_{1},y_{2},...,y_{m} $ ( $ 0<=y_{i}&lt;b_{y} $ ) — the digits of $ Y $ . There will be no leading zeroes. Both $ X $ and $ Y $ will be positive. All digits of both numbers are given in the standard decimal numeral system.

输出格式

Output a single character (quotes for clarity): - '<' if $ X&lt;Y $ - '>' if $ X&gt;Y $ - '=' if $ X=Y $

输入输出样例

输入样例 #1

6 2
1 0 1 1 1 1
2 10
4 7

输出样例 #1

=

输入样例 #2

3 3
1 0 2
2 5
2 4

输出样例 #2

<

输入样例 #3

7 16
15 15 4 0 0 7 10
7 9
4 8 0 3 1 5 0

输出样例 #3

>

说明

In the first sample, $ X=101111_{2}=47_{10}=Y $ . In the second sample, $ X=102_{3}=21_{5} $ and $ Y=24_{5}=112_{3} $ , thus $ X&lt;Y $ . In the third sample,  and $ Y=4803150_{9} $ . We may notice that $ X $ starts with much larger digits and $ b_{x} $ is much larger than $ b_{y} $ , so $ X $ is clearly larger than $ Y $ .