303990: CF767D. Cartons of milk

Memory Limit:256 MB Time Limit:2 S
Judge Style:Text Compare Creator:
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Description

Cartons of milk

题意翻译

Olya 每天喝 $k$ 瓶牛奶,她家里有 $n$ 瓶牛奶,超市里有 $m$ 瓶牛奶。 每瓶牛奶有一个保质期,$0$ 表示当天,$1$ 表示第二天, 以此类推,如果一瓶牛奶过了保质期,Olya 要把它扔掉。 为了不扔掉任何一瓶牛奶,求出她能够从商店里购买的最大牛奶的瓶数,并且按任意顺序输出购买的牛奶的编号(在输入顺序当中出现的位置),如果她连家里的牛奶都喝不完,输出 $-1$。 Translated by @Fuko_Ibuki

题目描述

Olya likes milk very much. She drinks $ k $ cartons of milk each day if she has at least $ k $ and drinks all of them if she doesn't. But there's an issue — expiration dates. Each carton has a date after which you can't drink it (you still can drink it exactly at the date written on the carton). Due to this, if Olya's fridge contains a carton past its expiry date, she throws it away. Olya hates throwing out cartons, so when she drinks a carton, she chooses the one which expires the fastest. It's easy to understand that this strategy minimizes the amount of cartons thrown out and lets her avoid it if it's even possible. ![](https://cdn.luogu.com.cn/upload/vjudge_pic/CF767D/609b94e7f0b8a5d407df0e97345c78713f56ad66.png)Milk. Best before: 20.02.2017.The main issue Olya has is the one of buying new cartons. Currently, there are $ n $ cartons of milk in Olya's fridge, for each one an expiration date is known (how soon does it expire, measured in days). In the shop that Olya visited there are $ m $ cartons, and the expiration date is known for each of those cartons as well. Find the maximum number of cartons Olya can buy so that she wouldn't have to throw away any cartons. Assume that Olya drank no cartons today.

输入输出格式

输入格式


In the first line there are three integers $ n $ , $ m $ , $ k $ ( $ 1<=n,m<=10^{6} $ , $ 1<=k<=n+m $ ) — the amount of cartons in Olya's fridge, the amount of cartons in the shop and the number of cartons Olya drinks each day. In the second line there are $ n $ integers $ f_{1},f_{2},...,f_{n} $ ( $ 0<=f_{i}<=10^{7} $ ) — expiration dates of the cartons in Olya's fridge. The expiration date is expressed by the number of days the drinking of this carton can be delayed. For example, a $ 0 $ expiration date means it must be drunk today, $ 1 $ — no later than tomorrow, etc. In the third line there are $ m $ integers $ s_{1},s_{2},...,s_{m} $ ( $ 0<=s_{i}<=10^{7} $ ) — expiration dates of the cartons in the shop in a similar format.

输出格式


If there's no way for Olya to drink the cartons she already has in her fridge, print -1. Otherwise, in the first line print the maximum number $ x $ of cartons which Olya can buy so that she wouldn't have to throw a carton away. The next line should contain exactly $ x $ integers — the numbers of the cartons that should be bought (cartons are numbered in an order in which they are written in the input, starting with $ 1 $ ). Numbers should not repeat, but can be in arbitrary order. If there are multiple correct answers, print any of them.

输入输出样例

输入样例 #1

3 6 2
1 0 1
2 0 2 0 0 2

输出样例 #1

3
1 2 3

输入样例 #2

3 1 2
0 0 0
1

输出样例 #2

-1

输入样例 #3

2 1 2
0 1
0

输出样例 #3

1
1 

说明

In the first example $ k=2 $ and Olya has three cartons with expiry dates $ 0 $ , $ 1 $ and $ 1 $ (they expire today, tomorrow and tomorrow), and the shop has $ 3 $ cartons with expiry date $ 0 $ and $ 3 $ cartons with expiry date $ 2 $ . Olya can buy three cartons, for example, one with the expiry date $ 0 $ and two with expiry date $ 2 $ . In the second example all three cartons Olya owns expire today and it means she would have to throw packets away regardless of whether she buys an extra one or not. In the third example Olya would drink $ k=2 $ cartons today (one she alreay has in her fridge and one from the shop) and the remaining one tomorrow.

Input

题意翻译

Olya 每天喝 $k$ 瓶牛奶,她家里有 $n$ 瓶牛奶,超市里有 $m$ 瓶牛奶。 每瓶牛奶有一个保质期,$0$ 表示当天,$1$ 表示第二天, 以此类推,如果一瓶牛奶过了保质期,Olya 要把它扔掉。 为了不扔掉任何一瓶牛奶,求出她能够从商店里购买的最大牛奶的瓶数,并且按任意顺序输出购买的牛奶的编号(在输入顺序当中出现的位置),如果她连家里的牛奶都喝不完,输出 $-1$。 Translated by @Fuko_Ibuki

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