Songs Compression

题意翻译

现有 $n$（$1 \le n \le {10}^5$）个物品，第 $i$ 个物品的重量为 $a_i$，可以进行 $1$ 次操作使 $a_i$ 变为 $b_i$（保证 $1 \le b_i<a_i \le {10}^9$）。 问最少多少次操作后能将所有物品装入空间为 $m$（$1 \le m \le {10}^9$）的背包。 若无论如何也无法完成，请输出 `-1`。

题目描述

Ivan has $ n $ songs on his phone. The size of the $ i $ -th song is $ a_i $ bytes. Ivan also has a flash drive which can hold at most $ m $ bytes in total. Initially, his flash drive is empty. Ivan wants to copy all $ n $ songs to the flash drive. He can compress the songs. If he compresses the $ i $ -th song, the size of the $ i $ -th song reduces from $ a_i $ to $ b_i $ bytes ( $ b_i < a_i $ ). Ivan can compress any subset of the songs (possibly empty) and copy all the songs to his flash drive if the sum of their sizes is at most $ m $ . He can compress any subset of the songs (not necessarily contiguous). Ivan wants to find the minimum number of songs he needs to compress in such a way that all his songs fit on the drive (i.e. the sum of their sizes is less than or equal to $ m $ ). If it is impossible to copy all the songs (even if Ivan compresses all the songs), print "-1". Otherwise print the minimum number of songs Ivan needs to compress.

输入输出格式

输入格式

The first line of the input contains two integers $ n $ and $ m $ ( $ 1 \le n \le 10^5, 1 \le m \le 10^9 $ ) — the number of the songs on Ivan's phone and the capacity of Ivan's flash drive. The next $ n $ lines contain two integers each: the $ i $ -th line contains two integers $ a_i $ and $ b_i $ ( $ 1 \le a_i, b_i \le 10^9 $ , $ a_i > b_i $ ) — the initial size of the $ i $ -th song and the size of the $ i $ -th song after compression.

输出格式

If it is impossible to compress a subset of the songs in such a way that all songs fit on the flash drive, print "-1". Otherwise print the minimum number of the songs to compress.

输入输出样例

输入样例 #1

4 21
10 8
7 4
3 1
5 4

输出样例 #1

2

输入样例 #2

4 16
10 8
7 4
3 1
5 4

输出样例 #2

-1

说明

In the first example Ivan can compress the first and the third songs so after these moves the sum of sizes will be equal to $ 8 + 7 + 1 + 5 = 21 \le 21 $ . Also Ivan can compress the first and the second songs, then the sum of sizes will be equal $ 8 + 4 + 3 + 5 = 20 \le 21 $ . Note that compressing any single song is not sufficient to copy all the songs on the flash drive (for example, after compressing the second song the sum of sizes will be equal to $ 10 + 4 + 3 + 5 = 22 > 21 $ ). In the second example even if Ivan compresses all the songs the sum of sizes will be equal $ 8 + 4 + 1 + 4 = 17 > 16 $ .