Web of Lies

题意翻译

有 $n$ 个人，$q$ 组询问。一开始这 $n$ 个人之间有 $m$ 条边相连。 有 3 种操作： - $1 \space u \space v (1 \le u,v \le n,u \ne v)$ 表示在 $u$ 和 $v$ 之间连一条边。保证 $u$ 和 $v$ 之间没有边。 - $2 \space u \space v (1 \le u,v \le n,u \ne v)$ 表示在 $u$ 和 $v$ 之间删一条边。保证 $u$ 和 $v$ 之间有边。 - $3$ 表示执行以下操作直至不可再执行为止。定义一个人的强度为其编号。在每个 **大小大于 1** 的连通块中找到强度最小的人，将这个人及其所连的边一同删去。在所有操作执行完毕后，请你输出还剩下多少人。**注意，每个 3 操作之间彼此独立**。即删人只是暂时的，这次操作结束之后所有被删的人连同边会复活。

题目描述

When you play the game of thrones, you win, or you die. There is no middle ground. Cersei Lannister, A Game of Thrones by George R. R. Martin There are $ n $ nobles, numbered from $ 1 $ to $ n $ . Noble $ i $ has a power of $ i $ . There are also $ m $ "friendships". A friendship between nobles $ a $ and $ b $ is always mutual. A noble is defined to be vulnerable if both of the following conditions are satisfied: - the noble has at least one friend, and - all of that noble's friends have a higher power. You will have to process the following three types of queries. 1. Add a friendship between nobles $ u $ and $ v $ . 2. Remove a friendship between nobles $ u $ and $ v $ . 3. Calculate the answer to the following process. The process: all vulnerable nobles are simultaneously killed, and all their friendships end. Then, it is possible that new nobles become vulnerable. The process repeats itself until no nobles are vulnerable. It can be proven that the process will end in finite time. After the process is complete, you need to calculate the number of remaining nobles. Note that the results of the process are not carried over between queries, that is, every process starts with all nobles being alive!

输入输出格式

输入格式

The first line contains the integers $ n $ and $ m $ ( $ 1 \le n \le 2\cdot 10^5 $ , $ 0 \le m \le 2\cdot 10^5 $ ) — the number of nobles and number of original friendships respectively. The next $ m $ lines each contain the integers $ u $ and $ v $ ( $ 1 \le u,v \le n $ , $ u \ne v $ ), describing a friendship. No friendship is listed twice. The next line contains the integer $ q $ ( $ 1 \le q \le 2\cdot {10}^{5} $ ) — the number of queries. The next $ q $ lines contain the queries themselves, each query has one of the following three formats. - $ 1 $ $ u $ $ v $ ( $ 1 \le u,v \le n $ , $ u \ne v $ ) — add a friendship between $ u $ and $ v $ . It is guaranteed that $ u $ and $ v $ are not friends at this moment. - $ 2 $ $ u $ $ v $ ( $ 1 \le u,v \le n $ , $ u \ne v $ ) — remove a friendship between $ u $ and $ v $ . It is guaranteed that $ u $ and $ v $ are friends at this moment. - $ 3 $ — print the answer to the process described in the statement.

输出格式

For each type $ 3 $ query print one integer to a new line. It is guaranteed that there will be at least one type $ 3 $ query.

输入输出样例

输入样例 #1

4 3
2 1
1 3
3 4
4
3
1 2 3
2 3 1
3

输出样例 #1

2
1

输入样例 #2

4 3
2 3
3 4
4 1
1
3

输出样例 #2

1

说明

Consider the first example. In the first type 3 query, we have the diagram below. In the first round of the process, noble $ 1 $ is weaker than all of his friends ( $ 2 $ and $ 3 $ ), and is thus killed. No other noble is vulnerable in round 1. In round 2, noble $ 3 $ is weaker than his only friend, noble $ 4 $ , and is therefore killed. At this point, the process ends, and the answer is $ 2 $ . In the second type 3 query, the only surviving noble is $ 4 $ . The second example consists of only one type $ 3 $ query. In the first round, two nobles are killed, and in the second round, one noble is killed. The final answer is $ 1 $ , since only one noble survives. 

题意翻译

有 $n$ 个人，$q$ 组询问。一开始这 $n$ 个人之间有 $m$ 条边相连。 有 3 种操作： - $1 \space u \space v (1 \le u,v \le n,u \ne v)$ 表示在 $u$ 和 $v$ 之间连一条边。保证 $u$ 和 $v$ 之间没有边。 - $2 \space u \space v (1 \le u,v \le n,u \ne v)$ 表示在 $u$ 和 $v$ 之间删一条边。保证 $u$ 和 $v$ 之间有边。 - $3$ 表示执行以下操作直至不可再执行为止。定义一个人的强度为其编号。在每个 **大小大于 1** 的连通块中找到强度最小的人，将这个人及其所连的边一同删去。在所有操作执行完毕后，请你输出还剩下多少人。**注意，每个 3 操作之间彼此独立**。即删人只是暂时的，这次操作结束之后所有被删的人连同边会复活。